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`U_(2) = (E_(1))/(2)``E_(2) = (E_(1))/(4)``K_(2) = - E_(2)``K_(2) = - (U_(2))/(2)`

Answer :

A::B::C::DSolution :

`E_(1) = - (GMm)/(R )` <br> `U_(2) = - (GMm)/(2R)` `(r = R + R = 2R)` <br> `K_(2) = (GMm)/(4R)` <br> and `E_(2) = - (GMm)/(4R)`